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4x^2+33x+50=0
a = 4; b = 33; c = +50;
Δ = b2-4ac
Δ = 332-4·4·50
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-17}{2*4}=\frac{-50}{8} =-6+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+17}{2*4}=\frac{-16}{8} =-2 $
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